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ISC 2027
All chaptersPhysics · Unit 8

Atoms and Nuclei

6 articles25 formulas32 ways the board asks it
PHYAtoms — Bohr Model & Spectra

Ionisation, Excitation & Spectral Lines

Ionisation energy is the energy needed to remove the electron entirely from an atom (take it from its level to n=∞n=\infty), while excitation energy lifts the electron from a lower level to a higher bound level. Both are just energy gaps read off Bohr's En=−13.6/n2 eVE_n = -13.6/n^2\,\text{eV} ladder, and when excited atoms fall back they emit a set of spectral lines counted by n(n−1)/2n(n-1)/2.

ISC examines this because it ties together the Bohr energy levels, the idea of bound versus free states, and the bookkeeping of how many distinct wavelengths a de-exciting gas produces.

Bohr energy levels of hydrogen
En=−13.6n2 eVE_n = -\dfrac{13.6}{n^{2}}\ \text{eV}
EnE_n is the energy of level nn, negative because the electron is bound. Ground state E1=−13.6 eVE_1=-13.6\,\text{eV}, then E2=−3.4 eVE_2=-3.4\,\text{eV}, E3=−1.51 eVE_3=-1.51\,\text{eV}, E4=−0.85 eVE_4=-0.85\,\text{eV}, approaching 00 as n→∞n\to\infty.
Ionisation energy from a level
Eion=E∞−En=0−(−13.6n2)=13.6n2 eVE_{ion} = E_\infty - E_n = 0 - \left(-\dfrac{13.6}{n^{2}}\right) = \dfrac{13.6}{n^{2}}\ \text{eV}
EionE_{ion} is the energy to free the electron from level nn (take it to n=∞n=\infty). From the ground state (n=1n=1) it is 13.6 eV13.6\,\text{eV} — the ionisation energy of hydrogen.
Excitation energy (lower to higher bound level)
Eexc=En2−En1=13.6(1n12−1n22) eVE_{exc} = E_{n_2} - E_{n_1} = 13.6\left(\dfrac{1}{n_1^{2}} - \dfrac{1}{n_2^{2}}\right)\ \text{eV}
n1n_1 is the starting (lower) level and n2n_2 the target (higher) level. From n=1n=1 to n=2n=2, Eexc=13.6(1−1/4)=10.2 eVE_{exc} = 13.6(1 - 1/4) = 10.2\,\text{eV} — the first excitation energy.
Number of spectral lines emitted
lines=n(n−1)2\text{lines} = \dfrac{n(n-1)}{2}
nn is the highest level the gas of atoms is excited to. For n=4n=4, this gives 4×32=6\dfrac{4\times 3}{2}=6 distinct lines, distributed among the Lyman (→1\to 1), Balmer (→2\to 2) and Paschen (→3\to 3) series.
  • Ionisation = excitation to n=∞n=\infty: it costs ∣En∣|E_n|, the magnitude of that level's energy. From the ground state of hydrogen this is exactly 13.6 eV13.6\,\text{eV}.
  • Excitation energy is the gap between two bound levels and is always less than the ionisation energy from the same starting level.
  • Read energies off the level ladder with their signs and subtract: Eexc=En2−En1E_{exc}=E_{n_2}-E_{n_1} comes out positive for an upward jump.
  • For a gas excited to level nn, the number of emission lines is n(n−1)/2n(n-1)/2 — every possible downward transition between the nn levels.
  • Sort the emitted lines by their final level: those ending on n=1n=1 are Lyman (UV), on n=2n=2 Balmer (visible), on n=3n=3 Paschen (IR). From n=4n=4 you get 33 Lyman, 22 Balmer and 11 Paschen line.
  • A single isolated atom makes only one jump at a time; the n(n−1)/2n(n-1)/2 count assumes a large collection of atoms taking all possible paths down.
  • Energies become less negative (closer to 00) as nn rises, so the levels crowd together near the top — successive excitation energies get smaller.
Where the marks go
  • Confusing ionisation with excitation: ionisation goes to n=∞n=\infty (electron freed), excitation goes to another bound level. From n=1n=1 these are 13.6 eV13.6\,\text{eV} and 10.2 eV10.2\,\text{eV} respectively.
  • Sign errors when subtracting level energies — keep both energies negative and subtract carefully so the excitation energy turns out positive.
  • Using nn or n2n^2 for the number of spectral lines instead of n(n−1)/2n(n-1)/2 (for n=4n=4 that is 66, not 44 or 1616).
  • Misassigning series — forgetting that lines ending on n=2n=2 (Balmer) are the visible ones, while n=1n=1 (Lyman) lines are ultraviolet.
How the board asks it
  • Numericalionisation and excitation energy from a level
    The ground state energy of hydrogen is −13.6 eV-13.6\,\text{eV}. Calculate the energy required to (i) ionise a hydrogen atom from the ground state and (ii) excite it from n=1n=1 to n=2n=2.
  • Numericalnumber of spectral lines n(n−1)/2n(n-1)/2
    A hydrogen atom is excited to the energy level n=4n=4. Calculate the number of spectral lines that can be emitted as the atoms return to the ground state.
  • Numericalexcitation energy as a gap between bound levels
    Using En=−13.6n2 eVE_n=-\dfrac{13.6}{n^2}\,\text{eV}, calculate the energy of the photon emitted when a hydrogen atom de-excites from n=3n=3 to n=2n=2, and state the series to which this line belongs.
  • Define / stateionisation vs excitation energy
    Define the terms ionisation energy and excitation energy of an atom.
  • Give reasonsionisation = excitation to n=∞n=\infty
    Give a reason why the ionisation energy of hydrogen from the ground state is greater than any of its excitation energies from the same state.

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Written for Sublevo. Question text quoted anywhere in these notes is the Council’s and carries its year and paper; the board’s own diagrams are not reproduced.