Sublevo
ISC 2027
All chaptersPhysics · Unit 2

Current Electricity

10 articles42 formulas58 ways the board asks it
PHYMeasuring Instruments

Potentiometer

A potentiometer measures potential difference and EMF by balancing an unknown against a uniform potential gradient along a long wire; at balance the device draws no current, so it reads true EMF without loading the cell. ISC uses it to compare two EMFs, to find the internal resistance of a cell, and to compute the potential gradient and balancing length.

The key idea is that balancing length is directly proportional to the potential being balanced.

Potential gradient
k=VLk = \dfrac{V}{L}
kk potential gradient (V/m or V/cm), VV potential difference across the whole wire, LL total wire length. Balanced PD on a length ll is Vl=k lV_l = k\,l.
Comparing two EMFs
E1E2=l1l2\dfrac{E_1}{E_2} = \dfrac{l_1}{l_2}
l1,l2l_1, l_2 balancing lengths for cells of EMF E1,E2E_1, E_2 under the same potential gradient. EMF is proportional to balancing length.
Internal resistance from a potentiometer
r=R(l1−l2l2)r = R \left( \dfrac{l_1 - l_2}{l_2} \right)
l1l_1 balancing length on open circuit (EMF), l2l_2 with shunt RR across the cell (terminal voltage), RR the external resistance. Uses r=R(E−V)/Vr = R(E-V)/V.
EMF from balancing length
E=k lE = k \, l
EE EMF balanced (V), kk potential gradient (V/cm), ll balancing length (cm). Rearranges to find l=E/kl = E/k for a known EMF.
  • At the balance point the galvanometer shows no deflection, so the test cell supplies zero current and the potentiometer reads true EMF (no IrIr drop).
  • The driver (auxiliary) cell must have EMF greater than any EMF being measured, otherwise no balance point exists on the wire.
  • Potential gradient k=V/Lk=V/L must be uniform — the wire needs constant cross-section and a steady driving current.
  • A potentiometer is more accurate than a voltmeter because a voltmeter always draws some current and reads terminal voltage, not EMF.
  • For internal resistance, l1l_1 corresponds to open-circuit EMF and l2l_2 to terminal voltage with the cell loaded by RR.
  • A longer wire (smaller kk) gives greater sensitivity because a given EMF balances over a longer, more readable length.
  • Balancing lengths can be used directly as proxies for voltages since both are proportional to kk.
Where the marks go
  • Inverting the internal-resistance formula — it is r=R(l1−l2)/l2r=R(l_1-l_2)/l_2, with the shorter loaded length l2l_2 in the denominator.
  • Forgetting the driver-cell EMF must exceed the measured EMF, otherwise the question has no balance point.
  • Mixing cm and m inconsistently between gradient and length so units of kk and ll do not cancel.
  • Treating the potentiometer like a voltmeter and assuming it reads terminal voltage rather than true EMF at balance.
How the board asks it
  • Numericalinternal resistance of a cell
    In a potentiometer experiment the EMF of a cell balances at a length l1=560 cml_1 = 560\,\text{cm}. When a resistance R=10 ΩR = 10\,\Omega is connected across the cell, the balancing length falls to l2=500 cml_2 = 500\,\text{cm}. Calculate the internal resistance of the cell.
  • Numericalcomparison of two EMFs and potential gradient
    A potentiometer wire of length 10 m10\,\text{m} carries a steady current. Two cells are balanced separately at 250 cm250\,\text{cm} and 400 cm400\,\text{cm}. Find the ratio of their EMFs. If the second cell has EMF 1.5 V1.5\,\text{V}, calculate the potential gradient of the wire in V m−1\text{V m}^{-1}.
  • Give reasonszero current at balance reads true EMF
    Explain why a potentiometer measures the EMF of a cell more accurately than a voltmeter does.
  • Diagram / graphcomparison of two EMFs setup
    Draw a labelled circuit diagram of a potentiometer used to compare the EMFs of two cells, and state the condition the driver cell must satisfy for a balance point to be obtained on the wire.
  • Give reasonssmaller gradient gives greater sensitivity
    Explain why the sensitivity of a potentiometer increases when the length of its wire is increased for a given driving current.
  • Define / statepotential gradient
    Define the potential gradient of a potentiometer wire and state the conditions necessary for it to remain uniform along the length of the wire.

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Written for Sublevo. Question text quoted anywhere in these notes is the Council’s and carries its year and paper; the board’s own diagrams are not reproduced.