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ISC 2027
All chaptersPhysics · Unit 3

Magnetism

7 articles31 formulas39 ways the board asks it
PHYExam Practice

Multiple Choice & Assertion-Reason

This is a chapter-wide revision article for the one-mark MCQs and Assertion-Reason items that sweep across all of magnetism: fields from currents, the magnetic force F⃗=qv⃗×B⃗\vec{F} = q\vec{v}\times\vec{B}, cyclotron motion, dipole torque and energy, meter conversions, and the Earth's field. These questions reward instant recall of the standard SI formulas and the qualitative behaviour (parallel velocity gives zero force, parallel wires with same-direction currents attract, etc.).

The Assertion-Reason items typically probe galvanometer sensitivity and the dip-angle limits, where one clean relation settles the answer.

Field at centre of a circular coil (NN turns)
B=μ0NI2RB = \dfrac{\mu_0 N I}{2R}
μ0=4π×10−7 T m A−1\mu_0 = 4\pi\times10^{-7}\ \mathrm{T\,m\,A^{-1}}, II current, RR radius, NN number of turns (a single turn gives μ0I/2R\mu_0 I/2R).
Lorentz magnetic force
F⃗=q v⃗×B⃗,F=qvBsin⁡θ\vec{F} = q\,\vec{v}\times\vec{B}, \qquad F = qvB\sin\theta
θ\theta is the angle between v⃗\vec{v} and B⃗\vec{B}; F=0F=0 when θ=0∘\theta=0^{\circ} (parallel) and maximum when θ=90∘\theta=90^{\circ}.
Cyclotron frequency
f=qB2πmf = \dfrac{qB}{2\pi m}
Independent of speed and radius; depends only on the charge-to-mass ratio q/mq/m and the field BB.
Torque and energy of a magnetic dipole
τ=mBsin⁡θ,U=−mBcos⁡θ\tau = mB\sin\theta, \qquad U = -mB\cos\theta
mm dipole moment, θ\theta angle between m⃗\vec{m} and B⃗\vec{B}; UU is minimum (−mB-mB) when m⃗∥B⃗\vec{m}\parallel\vec{B}.
Galvanometer sensitivities
SI=θI=NBAk,SV=SIGS_I = \dfrac{\theta}{I} = \dfrac{NBA}{k}, \qquad S_V = \dfrac{S_I}{G}
SIS_I current sensitivity, SVS_V voltage sensitivity, GG coil resistance, kk torsion constant, N,B,AN,B,A turns/field/area.
  • SI unit of magnetic dipole moment is A m2\mathrm{A\,m^2} (equivalently J T−1\mathrm{J\,T^{-1}}); SI unit of BB is the tesla T=Wb m−2\mathrm{T} = \mathrm{Wb\,m^{-2}}.
  • A charge moving parallel (θ=0∘\theta=0^{\circ}) or antiparallel (θ=180∘\theta=180^{\circ}) to B⃗\vec{B} feels zero force; the magnetic force never does work, so speed and kinetic energy stay constant.
  • Ammeter: low-resistance shunt SS in parallel. Voltmeter: high resistance RR in series. Mnemonic: an ammeter carries the large line current, so it must have tiny resistance.
  • Two long parallel wires attract if their currents are in the same direction and repel if opposite.
  • Inside a long solenoid the field is uniform and directed along the axis, B=μ0nIB=\mu_0 nI; outside it is nearly zero.
  • Dipole potential energy: minimum (−mB-mB) when m⃗∥B⃗\vec{m}\parallel\vec{B} (stable), zero at θ=90∘\theta=90^{\circ}, maximum (+mB+mB) when antiparallel (unstable).
  • Angle of dip is 0∘0^{\circ} at the magnetic equator and 90∘90^{\circ} at the magnetic poles.
  • Increasing turns NN raises current sensitivity SI=NBA/kS_I=NBA/k, but also raises coil resistance GG, so voltage sensitivity SV=SI/GS_V=S_I/G need not increase — this is the key to the standard A-R item.
Where the marks go
  • Mixing up μ0I/2R\mu_0 I/2R (centre of a loop) with μ0I/2πR\mu_0 I/2\pi R (long straight wire) — the π\pi only appears for the straight wire.
  • Stating that current sensitivity and voltage sensitivity always rise together; they do not, because SV=SI/GS_V = S_I/G and GG grows with NN.
  • Writing the dipole energy minimum as the perpendicular orientation; it is minimum when m⃗\vec{m} is parallel to B⃗\vec{B}.
  • Confusing the ammeter (shunt in parallel) with the voltmeter (high resistance in series).
How the board asks it
  • Assertion–Reasonvoltage vs current sensitivity
    Assertion (A): Increasing the number of turns NN in a moving-coil galvanometer always increases its voltage sensitivity. Reason (R): Current sensitivity is given by SI=NBA/kS_I=NBA/k, which rises with NN. Choose: (a) both A and R are true and R is the correct explanation of A; (b) both A and R are true but R is not the correct explanation of A; (c) A is true but R is false; (d) A is false but R is true.
  • Assertion–Reasonmagnetic force does no work
    Assertion (A): A charged particle that enters a uniform magnetic field moves with constant speed. Reason (R): The magnetic force F⃗=qv⃗×B⃗\vec{F}=q\vec{v}\times\vec{B} is always perpendicular to the velocity and so does no work on the particle. Choose: (a) both A and R are true and R is the correct explanation of A; (b) both A and R are true but R is not the correct explanation of A; (c) A is true but R is false; (d) A is false but R is true.
  • Assertion–Reasonangle of dip limits
    Assertion (A): At the magnetic equator the angle of dip is 0∘0^{\circ}. Reason (R): At the magnetic poles a freely suspended dip needle rests horizontal. Choose: (a) both A and R are true and R is the correct explanation of A; (b) both A and R are true but R is not the correct explanation of A; (c) A is true but R is false; (d) A is false but R is true.
  • Numericalfield at centre of a circular coil
    A circular coil of 5050 turns and radius 5 cm5\,\mathrm{cm} carries a current of 2 A2\,\mathrm{A}. Calculate the magnitude of the magnetic field at its centre. (μ0=4π×10−7 T m A−1)(\mu_0=4\pi\times10^{-7}\,\mathrm{T\,m\,A^{-1}})
  • Applicationforce between parallel currents
    Two long straight parallel wires carry currents in the same direction. State, with reason, whether the force between them is attractive or repulsive.
  • Define / stateSI unit of magnetic dipole moment
    State the SI unit of magnetic dipole moment and give one equivalent form of this unit.

Written for Sublevo. Question text quoted anywhere in these notes is the Council’s and carries its year and paper; the board’s own diagrams are not reproduced.