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d- and f-Block Elements

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CHEImportant Compounds

Potassium Dichromate: Preparation & Reactions

Potassium dichromate is prepared from chromite ore and is a key acidified oxidising agent. Exam focus: the preparation steps, the chromate–dichromate equilibrium, and balanced ionic oxidations in acidic medium.

Acidic-medium reduction half-reaction
Cr2O72−+14H++6e−→2Cr3++7H2OE∘=+1.33 VCr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O \qquad E^\circ = +1.33\ \text{V}
Cr goes +6→+3+6 \rightarrow +3, gaining 6 electrons per dichromate ion.
Chromate–dichromate equilibrium
2CrO42−+2H+⇌Cr2O72−+H2O2CrO_4^{2-} + 2H^+ \rightleftharpoons Cr_2O_7^{2-} + H_2O
acid shifts right (orange dichromate); alkali shifts left (yellow chromate).
Oxidation of Fe(II) by dichromate
Cr2O72−+14H++6Fe2+→2Cr3++6Fe3++7H2OCr_2O_7^{2-} + 14H^+ + 6Fe^{2+} \rightarrow 2Cr^{3+} + 6Fe^{3+} + 7H_2O
each Fe2+→Fe3+Fe^{2+}\rightarrow Fe^{3+} supplies one of the 6 electrons.
  • Preparation from chromite FeO⋅Cr2O3FeO\cdot Cr_2O_3: roast with Na2CO3Na_2CO_3 in air to yellow Na2CrO4Na_2CrO_4, acidify to orange Na2Cr2O7Na_2Cr_2O_7, then treat with KClKCl to crystallise K2Cr2O7K_2Cr_2O_7.
  • Chromate–dichromate equilibrium: 2CrO42−+2H+⇌Cr2O72−+H2O2CrO_4^{2-} + 2H^+ \rightleftharpoons Cr_2O_7^{2-} + H_2O; adding acid gives orange dichromate, adding alkali shifts it back to yellow chromate.
  • In acidic medium the half-reaction is Cr2O72−+14H++6e−→2Cr3++7H2OCr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O (E∘=+1.33E^\circ = +1.33 V).
  • Oxidation of iron(II): Cr2O72−+14H++6Fe2+→2Cr3++6Fe3++7H2OCr_2O_7^{2-} + 14H^+ + 6Fe^{2+} \rightarrow 2Cr^{3+} + 6Fe^{3+} + 7H_2O.
  • Oxidation of iodide: Cr2O72−+14H++6I−→2Cr3++3I2+7H2OCr_2O_7^{2-} + 14H^+ + 6I^- \rightarrow 2Cr^{3+} + 3I_2 + 7H_2O; oxidation of H2SH_2S: Cr2O72−+8H++3H2S→2Cr3++3S+7H2OCr_2O_7^{2-} + 8H^+ + 3H_2S \rightarrow 2Cr^{3+} + 3S + 7H_2O.
  • Cr2O72−Cr_2O_7^{2-} oxidises strongly in acidic medium because the 14H+14H^+ in the half-reaction drives it forward; in neutral or alkaline medium it converts to chromate, which is a poor oxidiser.
  • K2Cr2O7K_2Cr_2O_7 is a bright-orange crystalline solid, only moderately soluble in cold water, and is used as a primary standard in volumetric analysis because it is not deliquescent and can be obtained pure.
  • Structure: dichromate has two CrO4CrO_4 tetrahedra sharing one corner oxygen (a Cr–O–Cr bridge); both Cr are in the +6+6 state and tetrahedrally coordinated.
  • Oxidation of SO32−SO_3^{2-} (or SO2SO_2): Cr2O72−+8H++3SO32−→2Cr3++3SO42−+4H2OCr_2O_7^{2-} + 8H^+ + 3SO_3^{2-} \rightarrow 2Cr^{3+} + 3SO_4^{2-} + 4H_2O; the orange colour fades to green (Cr3+Cr^{3+}).
  • On heating, ammonium dichromate decomposes vigorously: (NH4)2Cr2O7→N2+Cr2O3+4H2O(NH_4)_2Cr_2O_7 \rightarrow N_2 + Cr_2O_3 + 4H_2O (the 'volcano' reaction).
  • The colour change orange (Cr2O72−Cr_2O_7^{2-}) to green (Cr3+Cr^{3+}) is the visual signal that dichromate has acted as an oxidant in acid.
Where the marks go
  • Balancing the oxidation in acidic medium with OH−OH^- on the wrong side; the acidic half-reaction uses 14H+14H^+ and produces 7H2O7H_2O with Cr3+Cr^{3+}.
  • Writing Cr2O72−Cr_2O_7^{2-} reduced to CrCr metal or leaving Cr as +6+6; it is reduced to Cr3+Cr^{3+} (a 6-electron change for two Cr).
  • Saying acid shifts the equilibrium toward chromate; acid gives the orange dichromate, alkali gives yellow chromate — students often reverse this.
  • Forgetting to multiply the reducing agent so electrons balance: 6 Fe2+Fe^{2+}, 6 I−I^-, or 3 H2SH_2S are needed per dichromate, not arbitrary coefficients.
  • Claiming dichromate is a strong oxidiser in alkaline medium; in base it becomes chromate, which is a weak oxidant.
How the board asks it
  • Conversionacidic-medium oxidation half-reactions
    Write the balanced ionic equation for the reaction of acidified K2Cr2O7K_2Cr_2O_7 with (i) Fe2+Fe^{2+} ions, (ii) iodide ions I−I^-, and (iii) hydrogen sulphide H2SH_2S.
  • Applicationpreparation from chromite ore
    Describe the preparation of K2Cr2O7K_2Cr_2O_7 from chromite ore FeO⋅Cr2O3FeO\cdot Cr_2O_3, giving balanced equations for the roasting with Na2CO3Na_2CO_3, the acidification, and the conversion to K2Cr2O7K_2Cr_2O_7 with KClKCl.
  • Give reasonsmedium-dependence of oxidising power
    Account for the fact that K2Cr2O7K_2Cr_2O_7 acts as a strong oxidising agent in acidic medium but is a poor oxidiser in alkaline medium.
  • Conversionchromate–dichromate equilibrium
    How will you convert a solution of potassium chromate into potassium dichromate, and then back into chromate? Give the ionic equations involved.
  • Structure / namingcorner-shared tetrahedra
    Draw the structure of the dichromate ion Cr2O72−Cr_2O_7^{2-}, indicating the oxidation state of chromium and the nature of the Cr−O−CrCr-O-Cr linkage.
  • Give reasonscolour change and primary standard
    Give reasons: (i) the orange colour of acidified K2Cr2O7K_2Cr_2O_7 turns green when it oxidises SO32−SO_3^{2-} to SO42−SO_4^{2-}; (ii) K2Cr2O7K_2Cr_2O_7 is used as a primary standard in volumetric analysis.

Practise this topic

Written for Sublevo. Question text quoted anywhere in these notes is the Council’s and carries its year and paper; the board’s own diagrams are not reproduced.